Форум MySQL

Как можно сгрупировать по нескольким параметрам?

[ip] [input] [output] [date] [errorcode]
192.168.0.1 - 500 - 500 - 2006-05-25 - 111
192.168.0.2 - 500 - 500 - 2006-05-25 - 111
192.168.0.3 - 500 - 500 - 2006-05-25 - 111
192.168.0.4 - 500 - 500 - 2006-05-25 - 111
192.168.0.5 - 500 - 500 - 2006-05-25 - 111
192.168.0.1 - 500 - 500 - 2006-05-25 - 111
192.168.0.2 - 500 - 500 - 2006-05-25 - 111
192.168.0.3 - 500 - 500 - 2006-05-25 - 111
192.168.0.4 - 500 - 500 - 2006-05-25 - 111
192.168.0.5 - 500 - 500 - 2006-05-25 - 111
192.168.0.1 - 500 - 500 - 2006-05-25 - 222
192.168.0.2 - 500 - 500 - 2006-05-25 - 222
192.168.0.3 - 500 - 500 - 2006-05-25 - 222
192.168.0.4 - 500 - 500 - 2006-05-25 - 222
192.168.0.5 - 500 - 500 - 2006-05-25 - 222
192.168.0.1 - 500 - 500 - 2006-05-25 - 222
192.168.0.2 - 500 - 500 - 2006-05-25 - 222
192.168.0.3 - 500 - 500 - 2006-05-25 - 222
192.168.0.4 - 500 - 500 - 2006-05-25 - 222
192.168.0.5 - 500 - 500 - 2006-05-25 - 222

как сделать запрос чтобы результат выглядел так:
[ip] [input] [output] [date] [errorcode]
192.168.0.1 - 1000 - 1000 - 2006-05-25 - 111
192.168.0.2 - 1000 - 1000 - 2006-05-25 - 111
192.168.0.3 - 1000 - 1000 - 2006-05-25 - 111
192.168.0.4 - 1000 - 1000 - 2006-05-25 - 111
192.168.0.5 - 1000 - 1000 - 2006-05-25 - 111
192.168.0.1 - 1000 - 1000 - 2006-05-25 - 222
192.168.0.2 - 1000 - 1000 - 2006-05-25 - 222
192.168.0.3 - 1000 - 1000 - 2006-05-25 - 222
192.168.0.4 - 1000 - 1000 - 2006-05-25 - 222
192.168.0.5 - 1000 - 1000 - 2006-05-25 - 222

я делал такой запрос
SELECT ip, sum(input), sum(output), date, errorcode
FROM log
WHERE date = 20060525
AND ip >= '192.168.0.0'
AND ip <= '192.168.255.255'
GROUP BY ip;

и на выходе
[ip] [input] [output] [date] [errorcode]
192.168.0.1 - 2000 - 2000 - 2006-05-25 - 222
192.168.0.2 - 2000 - 2000 - 2006-05-25 - 222
192.168.0.3 - 2000 - 2000 - 2006-05-25 - 222
192.168.0.4 - 2000 - 2000 - 2006-05-25 - 222
192.168.0.5 - 2000 - 2000 - 2006-05-25 - 222

Group by ip, errorcode

о как :)
спасибо